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25^2x=(1/125)^x+1
We move all terms to the left:
25^2x-((1/125)^x+1)=0
Domain of the equation: 125)^x+1)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
25^2x-((+1/125)^x+1)=0
We multiply all the terms by the denominator
25^2x*125)^x+1)-((+1=0
Wy multiply elements
3125x^3+1=0
We do not support expression: x^3
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